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A metal ball of specific heat capacity 400 joule per kgper celsius is allowed to fall from a height of 100 metre .If the ball on hitting the ground stops and all the energy possessed by it is converted into heat energy calculate the rise in temperature of the Ball (g = 200 metre per second square)

Respuesta :

First we'll calculate the energy it posesses

G.P.E = mgh = 0.2 * 10 * 100 = 200 J

Now we'll calculate the temperature rise

Q = m * c * (t2 - t1)
Q/(m * c) = t2-t1
t2 = Q/(m * c) + t1 = 200/(0.2 * 400) + 0 = 2.5 C

The branch of science which deals with matter is called physic.

The correct answer is 2.5C

The potential energy stored in the system is as followed:-

[tex]G.P.E = mgh = 0.2 * 10 * 100 = 200 J[/tex]

The formula is as follows to calculate the temperature rise

[tex]Q = m * c * (t_2 - t_1)\\\frac{Q}{(m * c)} = t_2-t_1\\t_2 = \frac{Q}{(m * c)} + t_1\\\\ = \frac{200}{(0.2 * 400)} + 0 \\\\= 2.5 C[/tex]

Hence, the correct answer is 2.5C

For more information, refer to the link:-

https://brainly.com/question/20293447

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