You can look for a factor of a 3 or 5 within the values 16 and 24.
24 can be factored as 3*8.
So you can break up the 24 in that way before multiplying,
and then have the 3's divide evenly out,
leaving you with a simpler problem.
[tex]\rm \frac3{16}\cdot\frac5{24}\quad=\quad \frac{3\cdot5}{16\cdot24}\quad=\quad \frac{3\cdot5}{16\cdot3\cdot8}\quad=\quad \frac{5}{16\cdot8}[/tex]
Is this what you were looking for perhaps?
