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The symbol for a radioactive nuclide is 131/56Ba Which statement is correct?
A) The atomic number of the radioactive nuclide is 75.
B) The mass number of the radioactive nuclide is 131.
C) The number of neutrons that are present in the nucleus of each atom is 56.
D) The number of protons that are present in the nucleus of each atom is 131.

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B.
The mass number of this nuclide is 131, its proton number is 56 and it has 131 - 56 = 75 neutrons.

Answer:

The correct answer is option B) The mass number of the radioactive nuclide is 131

Explanation:

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Among the isotopes of Barium is 131 / 56Ba. This means that the mass number (total protons plus neutrons) is 131. The atomic number (number of protons) is 56.

Then, 131-56 = 75 that is the number of neutrons.

After the analysis we conclude that the correct answer is option B) The mass number of the radioactive nuclide is 131

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