1) weight of the box: 980 N
The weight of the box is given by:
[tex]W=mg[/tex]
where m=100.0 kg is the mass of the box, and [tex]g=9.8 m/s^2[/tex] is the acceleration due to gravity. Substituting in the formula, we find
[tex]W=(100.0 kg)(9.8 m/s^2)=980 N[/tex]
2) Normal force: 630 N
The magnitude of the normal force is equal to the component of the weight which is perpendicular to the ramp, which is given by
[tex]N=W cos \theta[/tex]
where W is the weight of the box, calculated in the previous step, and [tex]\theta=50^{\circ}[/tex] is the angle of the ramp. Substituting, we find
[tex]N=(980 N)(cos 50^{\circ})=630 N[/tex]
3) Acceleration: [tex]7.5 m/s^2[/tex]
The acceleration of the box along the ramp is equal to the component of the acceleration of gravity parallel to the ramp, which is given by
[tex]a_p = g sin \theta[/tex]
Substituting, we find
[tex]W_p = (9.8 m/s^2)(sin 50^{\circ})=7.5 m/s^2[/tex]
We have that the Weight, normal force, acceleration is mathematically given as
Question Parameters:
A box with a mass of 100.0 kg slides down a ramp with a 50 degree angle.
Generally the equation for the Weight is mathematically given as
W=mg
W=9.81*100
W=981N
Generally the equation for the Normal force is mathematically given as
N=Fcos\theta
Therefore
N=100cos50
N=64.27N
Generally the equation for the acceleration is mathematically given as
A=sin\theta *g
Therefore
A=sin50 *9.81
A=0.76m/s^2
For more information on Mass visit
https://brainly.com/question/15959704
