What is the mass in grams of 13.06 mL of acetone
Acetone (fingernail-polish remover) has a density of 0.7857 g/cm3

Respuesta :

to know the mass of the acetone we must multiply the volume of the acetone with its density. but since the volume is in ml units and the density is in g/cm3. we must convert it firstsince 1 ml = 1 cm3
so mass acetone = 13.06 mL (0.7857 g/ml)mass acetone = 10.848 g

Answer : The mass of acetone will be, 10.26 grams.

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

[tex]Density=\frac{Mass}{Volume}[/tex]

Given :

Density of acetone = [tex]0.7857g/cm^3=0.7857g/mL[/tex]

Volume = 13.06 mL

Now put all the given values in the above formula, we get the mass of acetone.

[tex]0.7857g/mL=\frac{Mass}{13.06mL}[/tex]

[tex]Mass=10.26g[/tex]

Therefore, the mass of acetone will be, 10.26 grams.