[tex]\bf \qquad \textit{Compound Interest Amount}\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\qquad
\begin{cases}
A=\textit{current amount}\\
P=\textit{original amount }\to &\$19,900\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=\textit{times it compounds per year}\to &1\\
t=years\to &10
\end{cases}
\\\\\\
A=19,900\left(1+\frac{0.03}{1}\right)^{1\cdot 10}[/tex]
