b) No, it is not
c) x + 1 is a factor
Explanation:
[tex]b)\text{ }f(x)=x^3-7x^2+8x\text{ + 16}[/tex]
To determine if 10 is a function, we substitute x with 10 in the function:
[tex]\begin{gathered} f(10)\text{ = 1}0^3-7(10)^2\text{ + 8(10) + 16} \\ f(10)\text{ = 1000-700+80+16} \\ f(10)\text{ = }396 \end{gathered}[/tex]
No, it isn't a . This is because f(10) is not equal to zero, it is not a zero o. It has a remanider of 396.
c) Using synthetic division:
for x + 1: to be a factor, x = -1
+1 1 0
The last number is equal to zero. This indicates the remainder is zero.
Hence, x + 1 is a factor of the function f(x)
