The standard equation of a circle is given by:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
where (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.
For:
[tex]\begin{gathered} (x+3)^2+(y+1)^2=16 \\ \end{gathered}[/tex]
Rewrite the equation as:
[tex]\begin{gathered} (x-(-3))^2+(y-(-1))^2=4^2 \\ so\colon \\ h=-3 \\ k=-1 \\ r=4 \end{gathered}[/tex]
We can conclude it is a circle with center at (-3,-1) and radius of 4
