To calculate the number of barium atoms present in two moles of barium, we need to multiply the moles of barium by Avogadro's number (B)
A mole of a compound contains 6.022 x [tex]10^{23}[/tex] atoms.
6.022 x [tex]10^{23}[/tex] atoms is the Avogadro’s number which denotes the molecular weight in grams.
Thus, one mole of barium would have 6.022 x [tex]10^{23}[/tex] barium atoms
Therefore, two moles of barium would be multiplication of number of moles of barium by Avogadro’s number
Two moles of barium = 2 * 6.022 * [tex]10^{23}[/tex] = 12.044 * [tex]10^{23}[/tex]
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