Respuesta :
Considering the Combined Law Equation, the pressure of Cl₂ if the volume is increased to 0.800 l and the temperature increased to 55 °C is 114.367 mmHg.
Boyle's law
Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant: if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.
Mathematically, this law is expressed as:
P×V= constant
Gay-Lussac's law
Gay-Lussac's law states that the pressure of a gas is directly proportional to its temperature when the volume is constant: increasing temperature increases pressure, while decreasing temperature decreases pressure.
Mathematically, this law is expressed as:
P÷T= constant
Charles's law
Charles's law states that the volume is directly proportional to the temperature of the gas when the pressure is constant: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.
Mathematically, this law is expressed as:
V÷T= constant
Combined law equation
Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:
(P×V)÷T= constant
Considering an initial state 1 and a final state 2:
(P₁×V₁)÷ T₁= (P₂×V₂)÷ T₂
New pressure
In this case, you know:
- P₁= 475 mmHg
- V₁= 0.175 L
- T₁= 25 °C= 298 K (being 0 °C= 273 K)
- P₂= ?
- V₂= 0.800 L
- T₂= 55 °C= 328 K
Replacing in Combined law equation:
(475 mmHg× 0.175 L)÷ 298 K= (P₂× 0.800 L)÷ 328 K
Solving:
[(475 mmHg× 0.175 L)÷ 298 K] × (328 K÷ 0.800 L)= P₂
114.367 mmHg= P₂
Finally, the new pressure will be 114.367 mmHg.
Learn more about Combined Law Equation:
brainly.com/question/4147359
#SPJ1