4. Mrs. Sparks is a 9th grade Algebra 1 teacher. She teaches three
Algebra 1 courses and all the classes recently took a chapter exam.
Below are the scores.
Class 1
45
68
77
90
90
95
100
100
86
90
50
55
Class 2
64
65
70
40
100
87
84
88
90
90
95
80
Class 3
70
75
75
90
100
80
55
65
76
80
88
99
a. Find the mean, median, mode and range of Class 1.
b. Find the mean, median, mode and range of Class 2.
c. Find the mean, median, mode and range of Class 3.
d. Find the standard deviation of Class 1.
e. Find the standard deviation of Class 2.
f. Find the standard deviation of Class 3.
g. Which class had a higher standard deviation and what does that mean?
h. In your opinion, which class did better on the exam? Explain your answer.

Respuesta :

The mean of Class 1 is 78.83.

The median of Class 1 is  88

The mode of Class 1 is 90

The mean of Class 2 is 79.42

The median of Class 2 is 85.50

The mode of Class 2 is 90

The mean of Class 3 is 79.42

The median of Class 3 is 78

The mode of Class 3 are 75 and 80

The standard deviation of Class 1 is 18.81

The standard deviation of Class 2 is 16.15

The standard deviation of Class 3 is 12.70.

The class that had the higher standard deviation is class 1.

The class that did better on the exam is class 3 because it has the higher mean and the lowest standard deviation.

What is the mean, median and mode?

Mean is the average of a set of numbers.

Mean = sum of numbers / total number

Mean of Class 1 = (45 + 50 + 55 + 68 + 77 + 86 + 90 + 90 + 90 + 95 + 100 + 100) / 12 = 78.83

Mean of Class 2 = (40 + 64 + 65 + 70 + 80 + 84 + 87 + 88 + 90 + 90 + 95 + 100) / 12 = 79.42

Mean of Class 3 = (55 + 65 + 70 + 75 + 75 + 76 + 80 + 80 + 88 + 90 + 99 + 100) / 12 = 79.42

Median is the number that is at the center of the dataset that is arranged in either ascending or descending order.

Median of Class 1 = (86 + 90) / 2 = 88

Median of Class 2 =  (84 + 87) / 2 = 85.50

Median of Class 3 = (76 + 80) / 2 = 78

Mode is the number that occurs most frequently in a dataset.

Standard deviation is used to calculate the average variation of a dataset.

Standard deviation = [tex]\sqrt{\frac{(x - u)^{2} }{n} }[/tex]

Where:

  • x = number in the dataset
  • u = mean
  • n = total numbers in the dataset.

Standard deviation of Class 1 = 18.81

Standard deviation of Class 2 = 16.15

Standard deviation of Class 3 = 12.70

To learn more about standard deviation, please check: https://brainly.com/question/16555520

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Answer:

Down below!

Step-by-step explanation:

A.

The mean 78.83.

The median  88

The mode 90

The range 55

B.

The mean 79.42

The median 85.50

The mode 90

The range 60

C.

The mean 79.42

The median 78

The mode 75 and 80

The range 45

D. 18.81

E. 16.15

F. 12.70

G. The class that had the higher standard deviation is class 1.

H. The class that did better on the exam is class 3 because it has the higher mean and the lowest standard deviation.