The mass of sodium phosphate needed to make 375 mL (0.375 L) of a solution with a molarity of sodium ions of 0.900 M is 18.45 g.
Because each mole of sodium phosphate produces 3 moles of sodium ions upon dissociation, the molarity (c) of the sodium phosphate solution will be c = 0.900 M / 3
c = 0.300 M.
Now we can use the molarity and the volume of the solution (V) to find the required number of moles (n) of sodium phosphate.
c = n/V ⇒ n = c*V
n = 0.300 M * 0.375 L
n = 0.1125 mol
Finally, using the molar mass of sodium phosphate (M = 164 g/mol), we can calculate the mass (m) of sodium phosphate required:
n = m/M ⇒ m = n*M
m = 0.1125 mol * 164 g/mol
m = 18.45 g
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