a genetic experiment with peas resulted in one sample of offspring that consisted of green peas and yellow peas. a. construct a % confidence interval to estimate of the percentage of yellow peas. b. based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow? question content area bottom part 1 a. construct a % confidence interval. express the percentages in decimal form. enter your response herep enter your response here (round to three decimal places as needed.) part 2 b. based on the confidence interval, do the results of the experiment appear to contradict the expectation that 25% of the offspring peas would be yellow? yes, the confidence interval does not include 0.25, so the true percentage could not equal 25% no, the confidence interval includes 0.25, so the true percentage could easily equal 25%

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shomerajeshwari90 shomerajeshwari90 · Answer 1 · 2022-10-17T05:21:46+02:00

Null hypothesis : [tex]H_{0} : p=0.25[/tex]

Alternative hypothesis : [tex]H_{a};p\neq 0.25[/tex]

Given : A genetic experiment with peas resulted in one sample of offspring that consisted of 429 green peas and 159 yellow peas.

i.e. p=159/429=0.3706

For 95% level of confidence interval , significance level :

Critical value of z =[tex]Z_{a/2}[/tex]=1.96

Confidence interval for population proportion :

p±[tex]Z_{a/2}[/tex][tex]\sqrt{\frac{p(1-p)}{n} }[/tex]

=0.37±(1.96)[tex]\sqrt{0.37(1-0.37)/429[/tex]

=0.37±0.045687

=0.37±0.05

(0.32, 0.12)

Since 0.25 is not contained in the confidence interval , it means is not reasonable that the true proportion is 0.25 (25%).

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