Consequently, there exist four numbers z:
√3/2 ± I 1/2
-√3/2 ± I 1/2
The three unique vertices of an equilateral triangle are 0, z, and z3: (z^3=0)= e ^iπ/3(z -0 ) ⇔ z^3=e^(±iπ/3)z
=(z^2-e^±iπ/3)z=0⟺z=0
or z^2=e^±iπ/3
Since we have z[tex]\neq[/tex]0, z=e^±iπ/6= ±(√3/2 ± I 1/2 )
There are thus four numbers in z:
√3/2 ± I 1/2
-√3/2 ± I 1/2
learn more about of roots here
brainly.com/question/16932620
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