The parabolic equation that passes through the points is y = 29/7x^2 + -27/7x - 342/7
What are parabolic equations?
Parabolic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k
How to determine the equation of the parabola?
The given parameters are
x-intercepts (-3,0) and (4,0)
Point = (2,-40)
From the definition above, we have the form to be
y = ax^2 + bx + c
Substitute (-3,0) and (4,0) in the above equation
So, we have
0 = a(-3)^2 + b(-3) + c
0 = a(4)^2 + b(4) + c
This gives
9a -3b + c = 0
16a + 4b + c = 0
Substitute (2,-40) in the above equation y = ax^2 + bx + c
a(2)^2 + b(2) + c = -40
So, we have
4a + 2b + c = -40
The equations become
9a -3b + c = 0
16a + 4b + c = 0
4a + 2b + c = -40
Using a graphing tool, we have
a = 29/7, b = -27/7 and c = -342/7
So, we have
y = ax^2 + bx + c
This gives
y = 29/7x^2 + -27/7x - 342/7
Hence, the equation is y = 29/7x^2 + -27/7x - 342/7
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