Probability of locating an electron in an atom of hydrogen in its ground state is 0.439
Probability of finding the electron in the ground state of a hydrogen atom inside a sphere of radius," we are aware of the probability of finding the electron in a hydrogen atom.
p(r)=1−e⁻⁽²⁾⁽ᵃ⁾(1+2x+2x 2)
Where ,
x=r/a
Consequently, the likelihood that the electron will be found between the two shells mentioned in this case is given by
p(a<r<2a)=p(2a)−p(a)
p(a<r<2a)=[1−e −2x(1+2x+2x 2 )]on x=2 −[1−e 2x(1+2x+2x 2 )] x=1
p(a<r<2a)=0.439
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