In the reaction of 30.0 g of propane and 75.0 g of oxygen, oxygen is the limiting reagent.
The chemical equation of the reaction of propane and oxygen is as follows,
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
Here, 30 grams of propane reacts with 75 grams.
Step 1- First find the moles of oxygen and propane.
Moles of propane = mass/molar mass
Moles of propane = 44/30
Moles of propane = 1.21 moles.
Now, moles of oxygen = 75/18
Moles of oxygen = 4.16 moles.
Step2- compare the moles,
Now, we see, as per the reaction, for every one mole of propane. there should be 5 moles of oxygen, hence,
1 mole propane = 5 moles oxygen
1.21 moles propane = 6.05 moles of oxygen.
So, 6.05 moles of oxygen are required but we have only 4.16 moles, so, here, oxygen is the limiting reagent.
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