2.83 M will be the molar concentration of ethanol (CH₃CH₂OH, 46.08 g/mol) in a wine that is 14% ethanol by mass.
Molar mass of CH₃CH₂OH = 46.08 g/mol
Percentage in wine = 14 %
Density of wine = 0.93 g/cm3
Molar concentration = ?
Calculate density of ethanol:
density of ethanol = (% of ethanol / 100) × density of wine
density of ethanol = (14 / 100) 0.93 g/ml
density of ethanol = 0.14 × 0.93 g/ml
density of ethanol = 0.1302 g/ml
Supose we have 1 ml wine so mass = 0.1302 g / ml
Now calculate the number moles of ethanol
number of moles = mass / molar mass
number of moles of CH₃CH₂OH = 0.1302 g / 46.08 g/mol
number of moles of CH₃CH₂OH = 0.00283
Calculate the molarity of ethanol
molarity = number of moles / molar mass in L
molarity of CH₃CH₂OH = 0.00283 mol / 1 ml × 1000 ml / 1L
molarity of CH₃CH₂OH = 2.83 mol/L
molarity of CH₃CH₂OH = 2.83 M
You can also learn about molar concentrations from the following question:
https://brainly.com/question/13385951
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