suppose you need to make 400 ml of a solution with a ph of 14 at 298 what mass of sr(oh)2 should you add to a 400 ml volumetric flask

Respuesta :

Mass of Sr(OH)₂ should be added to a 400 ml volumetric flask is 24.34 gm.

Let the mass of Sr(OH)₂ = P g

Molar mass of Sr(OH)₂ = 121.63 g/mol

Mole of Sr(OH)₂ = P gm/ 121.63 g mol⁻¹ = 0.00822 × P mol

[Sr(OH)₂] = (0.00822 × P mol) / 0.400 L = (0.2055 × P) M

[OH⁻] = 2 × [Sr(OH)₂] = 0.0411 P M

pH = 14

pOH = 14 - 14 = 0

[OH⁻] = 10⁰ = 1

∴ 0.0411 P M = 1

⇒ P = 24.34 gm

Hence, mass of Sr(OH)₂ should be added to a 400 ml volumetric flask is 24.34 gm.

Learn more about mass of Sr(OH)₂ from the link given below.

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