The pH when 88.5 g of HBr is added will be 7.224
Molarity of HOCl = 0.332 M
Molarity of NaOCl = 0.405 M
Mass of HBr = 88,5 g
pH after adding 88.5 g HBr = ?
For acidic buffer we use the following formula:
pH =pKa + log (salt / acid)
pKa of HOCl = 7.54
pH = 7.54 + log (0.405 / 0.332)
pH = 7.54 + log 1.22
pH = 7.54 + 0.0864
pH = 7.623
Calculate the pH after adding 88.5 g HBr
First, calculate the number of moles of HBr added
number of moles = mass / molar mass
number of moles of HBr = 88.5 g / 80.91 g/mol
number of moles of HBr = 1.094 mol
Now the acidity of the solution will be:
acidity = 0.332 + 1.094
acidity = 1.426 mol
excess amount of salt = 1.094 - 0.405
excess amount of salt = 0.689 mol
pH = 7.54 + log (0.689 / 1.426)
pH = 7.54 + log 0.483
pH = 7.54 + (-0.316)
pH = 7.224
You can also learn about pH and molarity from the following question:
https://brainly.com/question/20000895
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