The compression work if the final state is 500 kpa will be 44.32KJ
Step-by-step explanation:
The stated circumstance is;
P₁= 1.0 MPa
T₁ = 250°C
M=0.6 Kg
v₂=0.4v₁
v₁=0.30661 m/sec
P₂=1 Mpa
T₂=250°C
repairs made to the piston;
W= mP(V2-V1),
W= 0.6*1,000(0.232-0.30661)
W= -44.32\J
illustrates the compression work using (- ve)
Since there is pressure in the final condition, the compression work is 44.32. (KJ)
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