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A 40 inch board i to be cut into three piece o that the econd piece i 3 time a long a the firt piece and the third piece i 4 time a long a the firt piece. X equal the length of the firt piece, find the length of all three piece

Respuesta :

The length of the first piece is 5 inches  , the length of second piece is 15 inches   and the length of third piece is 20 inches  .

In the question ,

it is given that

the second piece is given to be 3 times as long as the first piece ,

and the third piece is given to be  4 times as long as the first piece .

let the length of the first piece [tex]=[/tex] x ,

So , the length of second piece [tex]=[/tex] 3x

and the length of the third piece [tex]=[/tex] 4x ,

total length of the board = 40 inch ,

So the equation becomes , x + 3x [tex]+[/tex] 4x [tex]=[/tex] 40

8x = 40

x = 40/8

x = 5

the first piece = 5 inches

second piece = 3*5 = 15 inches

third piece = 4*5 = 20 inches

Therefore , The length of the first piece is 5 inches  , the length of second piece is 15 inches   and the length of third piece is 20 inches  .

The given question is incomplete , the complete question is

A 40 inch board is to be cut into three pieces so that the second piece is 3 times as long as the first piece and the third piece is 4 times as long as the first piece. X equal the length of the first piece, find the length of all three pieces ?

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