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a student heats a sample of hydrate once, and the mass of the sample and the evaporating dish is 17.296 g. after a second heating cycle, the mass of the sample and the dish is 14.025 g. the student stops the heat/cool/weigh cycle after the second time. if the original mass of the evaporating dish and the hydrate was 29.936 g, and the mass of the evaporating dish alone was 1.61 g, what is the mass of water removed from the sample by heating? provide your response to three digits after the decimal.

Respuesta :

Water weighs is 12.371 g.

What is the amount of water that was heated out of the sample?

Mevoporation dish weighs 1.135 g.

Mevoporating dish plus a sample of MHydrate equals 25.637g

Mfirst heated sample plus Mevoporating dish = 16.428g

Mevoporation dish plus a second hot sample equals 13.266g

Salt hydrate mass:

Serving of mevoporating = 1.135g

Mhydrated sample + Mevoporating dish = 25.637g

Mevoporating dish g = 25.637-1.135g=24.502g where Mhydrate sample is equal to 25.637g.

Anhydrous salt mass:

Serving of mevoporating = 1.135g

Second heated sample from a mevoporating dish weighs 13,266g

Msalt anhydrous = Msecond heated sample = 13.266-Mevoporating dish g = 13.266-1.135g = 12.131g

Volume of water:

Msalt anhydrous = 24.502-12.131g=12.371g where Mwater = Mhydrate sample

12.371 g for Mwater

The sample and the dish have a combined mass of 13.266 g following a second heating session. After the second time, the pupil ends the heat/cool/weigh cycle.

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