contestada

a mixture of sand and sodium chloride is found to be 48 percent sodium chloride by mass. how many moles of sodium chloride are in 74 g of this mixture?

Respuesta :

0.6078 moles of sodium chloride are in 74 gm of the mixture.

Mixture of sand and Nacl = 74gm

48% by mass is Nacl

48% = mass of Nacl / Total mass of mixture

48% = mass of Nacl / 74gm

Mass of Nacl = 48% of 74gm

Mass of Nacl = 48/100*74gm

Mass of Nacl = 35.52gm

Actual mass of Nacl = 58.44 gm

SO, the molar mass of Nacl = 35.52 / 58.44

                                               = 0.6078 moles

The molar mass of the chemical compound is defined as the mass of the sample of that compound divided by the amount of substance which is the number of moles in that sample.

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