1.0 L of carbon dioxide will be produced as a result of the combustion of 2.0L of methane gas and 2.0L of oxygen gas, under conditions of constant temperature and pressure
The reaction for the combustion of methane gas (CH4).
CH4(g)+2O2(g)⟶CO2(g)+2H2O(g)
The quantity of moles in a gas is exactly proportional to its volume under constant temperature and pressure. Therefore, based on the balanced equation, 1 L of methane (CH4) and 2 L of oxygen will combine to create 1 L of carbon dioxide (CO2) and 2 L of water.
As 2.0L of oxygen will completely react with 1.0L of methane, leaving 1.0L of methane unreacted, oxygen serves as the limiting reactant. 1.0L of carbon dioxide (CO2) will therefore be created.
Keep in mind that while the coefficients in stoichiometric equations (which represent the number of moles) are accurate, the number of significant figures is not constrained.
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