The probability of x being equal o 19.62 is d) 0.
It is given that x is normally distributed with a mean of 12 and a standard deviation of 3.
Now, Normal distribution is a continuous distribution.
This implies that the probability is measured over an interval, taking an infinite number of points in between.
If we plot a continuous distribution, the probability here at a point is not the value of the y coordinate at that point. Instead, it is seen as an area under the curve of the distribution, between the two intervals, say a and b.
Therefore, if we take up a single point say c, then the probability will be the area under the curve from c to c, which will obviously be 0.
Hence, the probability that x = 19.62 will be 0.
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