The mixture contains 250 mg of lactose as diluent.
Total mixture = 1.25 g
1x + 4x = 1.25 g
5x = 1.25g
x = 1.25 / 5
x = 0.25 g
lactose = 0.25 g = 250 milligram.
Thus in the mixture containing codeine sulfate, with lactose as an inert diluent, 250 mg of lactose is present.
To learn more about mixture click here:
https://brainly.com/question/6358654
#SPJ4