The electron will move to energy level
n =1 ..
We have, an electron in the n= 5 level of an Hydrogen atom emits a photon of wavelength 94.98nm...
Using the Rydberg formula ,
1/ λ = R ( 1/ n²ⱼ- 1/n²ᵢ)
where, lambda ----> wavelength of photon
nⱼ----> excited energy level
nᵢ---> initial energy level at which electron of hydrogen atom emits photon
R -----> Rydberg constant
photon are packet of energy.
we have give nᵢ = 5 , lambda = 94.98nm = 94.98×10⁻⁹m
R = constant = 1.097× 10⁷ m⁻¹
Substitute the values in formula we get ,
10⁹/ 94.98 = 1.097× 10⁷ ( 1/ n²ⱼ - 1/ 25) ⇒ 1/ n²ⱼ - 1/25 = 10^2/94.98×1.097 = 0.95975.68 ⇒ 1/n²ⱼ= 0.99975 ⇒ n²ⱼ= 1.00024 => nj = 1.00012
So, the electron moves from n= 5 energy level to to n= 1 energy level.
To learn more about Spectrum of hydrogen atom, refer:
https://brainly.com/question/28490374
#SPJ4
