contestada

if you wish to prepare a 1.72 m solution of nano3, to what volume (in liters) would you have to dilute 31.9 ml of 3.45 m nano3?

Respuesta :

To prepare a 1.72 m solution of nano3, the volume (in liters) which would you have to dilute 31.9 ml of 3.45 m NaNO3 is 63.9 ml.

This problem can be solved by using the concept of molarity.

What is Molarity?

Molarity is defined as the ratio of moles of solute to the volume of solution.

Mathematically,

Molarity = moles of solute / volume of solution

Step 1 : Calculation of moles

Given,

Concentration of NaNO3 = 3.45 m

Volume of NaNO3 = 31.9 ml

As we know that,

Concentration = mole / volume

By substituting all the values, we get

3.45 m = mole / 31.9

Mole = 3.45 × 31.9

Moles of NaNO3 = 110.05 mol

Step 2 : Calculation of Volume

Moles of NaNO3 = 110.05 mol

Molarity of NaNO3 = 1.72 m

By substituting all the values, we get

1.72 m = 110.05 / volume

Volume = 110.05 / 1.72 = 63.9 ml

Thus, we concluded that to prepare a 1.72 m solution of nano3, the volume (in liters) which would you have to dilute 31.9 ml of 3.45 m NaNO3 is 63.9 ml.

learn more about Molarity:

https://brainly.com/question/19517011

#SPJ4

Otras preguntas