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You are at a furniture store and notice that a Grandfather clock has its time regulated by a physical pendulum that consists of a rod with a movable weight on it. When the weight is moved downward, the pendulum slows down; when it is moved upward, the pendulum swings faster. If the rod has a mass of 1.23 kg and a length of 1.25 m and the weight has a mass of 1.99 kg, where should the mass be placed to give the pendulum a period of 2.00 seconds? Measure the distance in meters from the top of the pendulum.
I think the equation for this problem is T= 2pi * sqrt ( I / mgd), where I = md^2
The reason why I think that is because it is no a simple pendulum, it is a physical pendulum which means that a hanging object hangs about a fixed axis that does not pass through its center of mass.

Respuesta :

The distance in meters from the top of the pendulum is 0.9939 m and Yes the equation will beT= 2pi * sqrt ( I / mgd).

A simple pendulum consists of a mass m hanging at the end of a string of length L. The period of a pendulum or any oscillatory motion is the time required for one complete cycle, that is, the time to go back and forth once.

If the amplitude of motion of the swinging pendulum is small, then the pendulum behaves approximately as a simple harmonic oscillator, and the period T of the pendulum.

Periodic Motion is based on the concept of periodic motion. Periodic motion can be defined as any motion that repeats over and over again with the same time required for each recurrence. A period is the amount of time for the system to complete one cycle.

In this example, it is the amount of time for the energy sphere to be released and then return to its approximate release point. The frequency is the number of cycles per unit of time, i.e., how many cycles are completed in one minute.

Given,

length = 1.25 m

mass =1.23 kg

T = 2πsqrt(l/g)

2 = 2 *3.14 sqrt(l/9.8)

l = 0.9939 m

To know more about pendulum here

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