electronic watches keep accurate time using crystal oscillators. inside the watch, there is a tiny block of quartz which vibrates. two opposite faces of the block move alternately toward each other and away from each other. this is a caused by a standing wave in the block. the two opposite faces are at antinodes, and the plane halfway between these two faces is at a node. if the two faces are 7.79 mm apart and the speed of sound in quartz is 3.72 km/s, find the frequency of the vibration.

The frequency of a repeated event is its number of instances per unit of time. It is measured in hertz and corresponds to one event per second. Time period is the reciprocal of frequency as period is the time interval between events.

Frequency is an important parameter used in science to describe the speed of vibrations and vibrational phenomenon such as mechanical vibrations, audio signals, radio waves and light.

Now, let us calculate the frequency of vibration,

λ/4 + λ/4 = 7.79 mm

λ = 2* 7.79 = 15.58 mm = 15.58 * 10⁻³ m

We know that,

f = v/ λ = (3.72* 10³)/15.58 * 10⁻³ = 0.238 * 10⁶ Hz = 238.76 kHz

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