A random sample of n measurements was selected from a population with unknown mean and standard deviation o = 20 for each of the situations in parts a through d. Calculate a 95% confidence interval for ju for each of these situations. a. n=70, X = 27 b. n = 150, x= 115 c. n= 80. x = 18 d. n = 80, x=5.33 e. Is the assumption that the underlying population of measurements is normally distributed necessary to ensure the validity of the confidence intervals in parts a through d? Explain. (Round to two decimal places as needed.) (Round to two decimal places as needed.) (Round to two decimal places as needed.) d. (ID) (Round to two decimal places as needed.) e. Choose the correct answer below. O A. No, since the sample sizes are large in 2 30), the condition guarantees that the sampling distribution of x is approximately normal. O B . No, since the confidence level is at least 90%, the underlying distribution need not be normal. OC. No, since the sample was randomly selected from the target population, the sampling distribution of x is guaranteed to be approximately normal. OD. Yes, the underlying distribution must be normal for the validity of these confidence intervals O E. No, since the sample sizes are large in 230) and randomly selected from the target population, the condition guarantees that the sampling distribution of x is approximately normal.

Respuesta :

As per the 95% confidence interval for the population mean is (31.042, 42.958).

What is meant by confidence interval?

In math, A normal distribution with a mean, μ  and standard deviation, σ  is used to estimate the confidence interval for the unknown population mean.

Here we have given that the random sample of n measurements was selected from a population with unknown mean and standard deviation o = 20 for each of the situations.

And we need to find the 95% confidence interval for ju for each of these situations.

Here we are given the following data:

   • Sample size, n=70

   • Sample mean, ¯x=37

   • Population standard deviation, σ=20

Then the 95% confidence interval for the population mean is defined as:

=> x±z0.01/2×σ√n

Here by applying Excel function for the confidence coefficient: 

=> NORM.INV(0.01/2,0,1)

Then we get,

=> 37±2.58×20√75(31.042, 42.958)

To know more about Confidence interval here.

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