A 12-bit analog to digital data capture module may accept input voltages between 0 and 10. The least important bit is 2.441 millivolts.
The objective is to find the following and calculate the least significant bit
given,
A 12-bit analog to digital data N=12
The input range of 0vdc to +10vdc
LSB of DAC=[tex]V_{ref} (+)-V_{ref}(-)[/tex]
Here, N=12
[tex]V_{ref}[/tex](+)=10V
[tex]V_{ref}[/tex](-)=0
CSB of DAC=10-0/12
=10/4096
=2.441
∴CSB of DAC=2.441 mV
Digital data is information that, in information theory and information systems, is represented as a series of discrete symbols, each of which can only take one of a limited set of values from an alphabet, such as a letter or a number. Using a text document as an example, which is made up of a long string of alphabetic characters Modern information systems most frequently use binary data, which is a string of binary digits (bits) that can each have one of two values, either 0 or 1. Binary data is the most prevalent type of digital data and is represented by a binary digit (bit) string.
A value from a continuous range of real numbers is used to represent analog data, in contrast to digital data, which is represented by a digital value. A continuous analog signal, which also takes on the form of analog data, transmits it.
Learn more about Digital data here:
https://brainly.com/question/11983430
#SPJ4