Respuesta :
In cell X, which has the A fate, gene 1 is on. In cell Y, which has the B fate, gene 1 is off. If there is a loss of-function mutation in both Gene 3 and Gene 5 then Cell X will have the B fate and cell Y will have the B fate.
Genes that have sequence mutations can produce a wide range of alleles, or variants, in the population. These alleles may produce slightly varied phenotypic traits as a result of encoding slightly various copies of the same gene.
A particular allele of a common gene is usually referred to as "carrying a gene" in scientific literature. Natural selection/survival of the fittest and genetic drift of alleles are two methods that cause genes to evolve.
As new events are uncovered, the understanding of genes is always being refined. A gene's coding regions, for instance, might be divided up into a number of exons, whereas the gene's regulatory elements might be located outside of them. Instead of DNA, some viruses store their genomes in RNA.
To learn more about genes click on the given link: brainly.com/question/8832859
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The complete question is:
Below is a signaling pathway that determines the fate of cells X and Y [note that a pointed arrow ( → ) indicate activation and the blunt arrow ( ---| ) indicates inhibition].
1 → 2 ---| 3 ---| 4 → 5 ---| 6
In cell X, which has the A fate, gene 1 is on. In cell Y, which has the B fate, gene 1 is off. What will happen if there is a loss of-function mutation in both Gene 3 and Gene 5?
Question options:
a) Cell X will have the A fate and cell Y will have the B fate.
b) Cell X will have the A fate and cell Y will have the A fate.
c) Cell X will have the B fate and cell Y will have the B fate.
d) Cell X will have the B fate and cell Y will have the A fate.
e) There is not enough information to answer this question.
