apply the rule of multiplication to a dihybrid cross. how would you determine the probability of getting an f2 offspring that is homozygous recessive for both traits?

Respuesta :

Dihybrids create four different kinds of gametes. A gamete has a 1/4 chance of carrying both recessive alleles, and two of them joining together has a 14 × 14 or 116 chance.

The likelihood that both of the organism's genes are recessive is 50% x 50% = 25%. T. Krishan 25% (1/4th) of the offspring from the specified dihybrid cross would be homozygous both for characteristics. The Punnett square below shows that there is a 25% chance of having a healthy homozygous (AA) kid, a 50% probability of having a heterozygous (Aa) carrier child, and a 25% risk of having a homozygous recessive (aa) kid that will likely die from this condition. A Punnett square can be used to forecast this ratio in order to illustrate potential results of a gene sequence.

Learn more about dihybrid

https://brainly.com/question/12540319

#SPJ4