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According to simple valence bond theory (no promotion/hybridization), which of the following species would not form a bond with carbon? Consider the electronic configuration of the ground state of the element
(a) LiC
(b) BeC
(c) BC
(d) C2
(e) CN

Respuesta :

BeC will will not form a pair because no free element is available with Be.

The elements given in the above question is as follow,

Now consider the ground state of given element we get,

[tex]Li=1s^2,2S^1\\Be=1s^2,2S^2\\B=1s^2,2S^2,2p^1\\C=1s^2,2S^2,2p^2\\N=1s^2,2S^2,2p^3[/tex]

Now, for balance bond theory,

Consider,

a) LiC

[tex]Li=1S^2,2S^1\\C=1S^2,2S^2,2P^2[/tex]

It will form a bond because unpaired electrons are present.

b)Bec

[tex]Be=1s^2,2S^2\\C=1s^2,2S^2,2p^2[/tex]

If will not form a pair because no free element is available with Be.

c)BC

[tex]B=1s^2,2S^2,2p^1\\C=1s^2,2S^2,2p^2[/tex]

It will form a bond because unpaired electrons are present in Boron and carbon.

d)[tex]C_2[/tex]

[tex]C=1s^2,2S^2,2p^2[/tex]

It will form a bond because unpaired electrons are present.

e)CN

[tex]C=1s^2,2S^2,2p^2\\N=1s^2,2S^2,2p^3[/tex]

It will form a bond because unpaired electrons are present.

For more such question on valence bond.

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