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Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 22.0 and carries a clockwise current of 15.0 , as viewed from above, and the outer wire has a diameter of 40.0. What must be the direction (as viewed from above) of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires? What must be the magnitude of the current in the outer wire so that the net magnetic field due to this combination of wires is zero at the common center of the wires?

Respuesta :

The current in the outer wire is in the counterclockwise direction.

The concept of the right-hand thumb rule and magnetic field at the center of a current carrying loop is required to solve the problem.

First, determine the direction of the current in the outer wire by using the right-hand thumb rule. Then, calculate the magnitude of current in the outer wire by equating the sum of magnetic fields due to each wire to zero.

The magnetic field at the center of a current loop is, B = [tex]\mu[/tex]₀I/2R

Here, I is the current through the loop, R is the radius of the loop, and

[tex]\mu[/tex]₀ is the permeability of free space.

The right-hand thumb rule is used to find the direction of the magnetic field. Curl the fingers of the right hand into a half circle in such a way that the thumb points in the direction of the current, then the fingers will point in the direction of the magnetic field.

Learn more about The magnetic field here:- https://brainly.com/question/14411049

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