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Suppose your waiting time for a bus in the morning is uniformly distributed on [0, 12], whereas waiting time in the evening is uniformly distributed on [0, 14] independent of morning waiting time.(a) If you take the bus each morning and evening for a week, what is your total expected waiting time? (Assume a week includes only Monday through Friday.) [Hint: Define rv'sX1, , X10and use a rule of expected value.]min(b) What is the variance of your total waiting time? (Round your answer to two decimal places.)min2(c) What are the expected value and variance of the difference between morning and evening waiting times on a given day? (Use morning time − evening time. Round the variance to two decimal places.)expected value minvariance min2(d) What are the expected value and variance of the difference between total morning waiting time and total evening waiting time for a particular week? (Use morning time − evening time. Assume a week includes only Monday through Friday.)expected value minvariance min2

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varshamittal029

The total expected waiting time including the morning and the evening time is 41/3

given that your waiting time for a bus in the morning is uniformly distributed on [0, 8], whereas waiting time in the evening is uniformly distributed on [0, 10] independent of morning waiting time.

Sum of both waiting times = X+Y

Where X = morning wait time is U(0.8) and

Y = evening wait time is U(0,10)

Since X and Y are independent

Var(x+y) = Var(x)+Var(y)

Var(x) = (8^2 - 0^2)/12 = 16/3

Var(Y) = (10^2 - 0^2)/12 = 25/3

Var(x+y) = 16/3 + 25/3

= (16 + 25)/3

= 41/3

Therefore, the total expected value of waiting time including the morning and the evening time is 41/3.

To learn more about variance refer here

https://brainly.com/question/15858152

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