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For each trial, calculate the moles of KHP used to neutralize the NaOH solution and put the answer in the Results Table. (Hint: Use the correct formula from the Discussion section to calculate the molar mass of KHP! It is NOT the mass of K + H + P!)
For each trial, using the mole ratio from the balanced equation, calculate the moles of NaOH and put the answer in the Results Table.
For each trial, calculate the molar concentration of the NaOH solution and put the answer in the Results Table. (See example in the discussion.)
Calculate the average molarity and enter this answer in your Results Table.
Submit your Results Table and Calculations in the following corresponding question boxes.
1.Moles of KHP for Trial 1,2,3,4
2.Moles of NaOH for Trial 1,2,3,4
3.Molarity of NaOH (M) for trial 1,2,3,4
4. Average Molarity of NaOH (M)

Respuesta :

rafikiedu08

1. The number of moles of KHP is found by dividing the mass of KHP by the molecular weight of KHP.

2. The number of moles of NaOH is found by multiplying the moles of KHP by the mole ratio of NaOH to KHP given by the above, balanced chemical reaction.

It will be presumed that more KHP is present in the solution if additional NaOH is added. As a result, the % KHP will be higher than anticipated. If the concentration of NaOH is doubled, just half the volume from the initial experiment is needed. To titrate NaOH with KHP, add NaOH from the burette to a predetermined amount of KHP. The mass and volume of KHP utilized to create the KHP solution are used to calculate the molarity of the KHP solution. The molarity of the NaOH is then determined using the information from the titration.

To learn more about number of moles visit:https://brainly.com/question/14919968

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