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Consider independent simple random samples that are taken to test the difference between the means of two populations. The variances of the populations are unknown, but are assumed to be equal. The sample sizes of each population are n1 = 37 and n2 = 45. The appropriate distribution to use is the:
rev: 12_26_2015_QC_CS-36924
t distribution with df = 81.
t distribution with df = 82.
t distribution with df = 41.
t distribution with df = 80.

Respuesta :

varshamittal029

The appropriate distribution to use is t distribution with df = 80.

Variance

  • The variance of a random variable is the expected squared deviation from its population mean or sample mean.
  • Variance is a measure of dispersion, which means it measures how far apart a set of numbers is from their average value.

Distribution

  • A probability distribution is a mathematical function that calculates the chances of various possible outcomes for an experiment.
  • It is a mathematical description of a random phenomenon in terms of its sample space and event probabilities (subsets of the sample space).

Given that:

n1 = 37

n2 = 45

The variances of the populations are not know so we can use t distribution

Degree of freedom = n1 + n2 - 2

                                = 37 + 45 - 2

                                = 80

Therefore, t distribution with df = 80

To learn more about distribution check the given link

https://brainly.com/question/12385304

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