A report on food science states that younger adults are more likely to see foods with genetically modified ingredients as being bad for their health than older adults. This statement is based on a representative sample of 175 adult Americans age 18 to 29 and a representative sample of 450 adult Americans aye 50 to 61. of those in the 18 to 29 age group, 48% they believed these foods were bad for their health, while only 38% of those in the 50 to 64 age group believed this USE SALT (a) Are the sample sizes large enough to use the large-sample confidence interval to estimate the difference in the population proportions? Explain Select Let 0.48 and -0.38. - 175 and ng = 450, where the 1 subscript indicates the age 18-29 group and the 2 subscript indicates the age 50-64 group. Since P.- ..(1-P) and (1-P) - Select all at least 10, the sample sizes Select Large enough to be the large-sample confidence interval (b) Estimate the difference in the proportion of adult Americans age 18 to 29 who believe the foods made with genetically modified ingredients are bad for their health and the corresponding proportion for adult Americans age 50 to 64. Use a 90% confidence interval. (Use P.-P. Use a table or SALT. Round your answers to four decimal places) (c) Is zero in the confidence interval? Yes O NO What does this suggest about the difference in the two population proportions? This means that it is plausible that the two population proportions could be equal This means that it is not plausible that the two population proportions could be equal,

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A report on food science states that younger adults are more likely to see foods with genetically modified ingredients as being bad for their health than older adults. is

What is ingredients?

A component of a mixture is referred to as an ingredient. For instance, when cooking, recipes detail the items needed to produce a particular dish. Numerous commercial products allegedly outperform rival products by using secret components.

a) Are the sample sizes large enough to use the large-sample confidence interval to estimate the difference in the population proportions and

[tex]$-$ Select-v . Let $\hat{p}_1=0.48$ and $\hat{p}_2=0.38, n_1=175$ and $n_2=450$, where the 1 subscript indicates the age $18-29$ group and the 2 subscript indicates the age 50 64 group. Since $n_1 \hat{p}_1=\square, n_1\left(1-\hat{p}_1\right)=\square, n_2 \hat{p}_2=$ , and $n_2\left(1-\hat{p}_2\right)=$ -Select-V all at least 10 , the sample sizes large enough to use the large-sample confidence interval.[/tex]

(b) Estimate the difference in the proportion of adult Americans age 18 to 29 who believe the foods made with genetically modified ingredients are bad for their health and the corresponding proportion for adult [tex]Americans age 50 to 64 . Use a $90 \%$ confidence interval. (Use $p_1-p_2$. Use a table or SALT. Round your answers to four decimal places.)[/tex]

(c) Is zero in the confidence interval?

No This means that it is not plausible that the two population proportions could be equal.

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