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Place the following compounds in order of decreasing strength of intermolecular forces. I. CH3CH2CH2CH2CH2CH3 II. (CH3)3CCH3 IIL (CH3)3CCH2CH3 1) C) II >III> I 2) Identify the compound with the lowest boiling point. A) CH3CN B) CH3CHO C) CH3CH2CH3 D) (CH3)20 E) CH3OCH3 2) 3) Place the following substances in order of increasing vapor pressure at a given temperature SF6 SiH4 SF4 3) A) SiH4

Respuesta :

The following compounds are listed in decreasing order of intermolecular force strength:

CH₃CH₂CH₂CH₂CH₂CH₃ > (CH₃)₃CCH₂CH₃ > (CH₃)₃CCH₃

1) The following compounds are listed in decreasing order of intermolecular force strength: as branching grows, intermolecular force falls, or as surface area reduces, intermolecular force increases.

CH₃CH₂CH₂CH₂CH₂CH₃ > (CH₃)₃CCH₂CH₃ > (CH₃)₃CCH₃

2) The lowest boiling point and weakest van der wall forces are seen in the combination CH3CH2CH3.

3) The compounds listed below, in ascending sequence of increasing vapour pressure at a specific temperature, are as follows:

SF₄ < SF₆ < SiH₄  

The most polar molecule and one with the lowest vapour pressure is SF4.

To learn more about intermolecular force Please click on the given link:

brainly.com/question/14774937

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