Figure 7-40 shows a cord attached to a cart that can slide along a frictionless horizontal rail aligned along an x axis. The left end of the cord is pulled over a pulley, of negligible mass and friction and at cord height h = 1.6 m, so the cart slides from x1 = 5.0 m to x2 = 1.0 m. During the move, the tension in the cord is a constant 28.0 N. What is the change in the kinetic energy of the cart during the move?

Respuesta :

The cord's tension remains constant during the movement at 28.0 N. 94.08 J is the change in the cart's kinetic energy during motion.

the force exerted on the cart is the tension T in the chord itself. so,

F=T

Calculate the displacement of the cart.

d=[tex]\sqrt{x_{1}^{2}+h^{2} } -\sqrt{x_{2}^{2}+h^{2} }[/tex]

subsitute 5.0m for x₁,1.0m for x₂,and 1.60m for h.

d=[tex]\sqrt{5.0^{2}+1.60^{2} } -\sqrt{1.0^{2}+1.60^{2} }[/tex]

d=3.36m

calculate the change in kinetic energy of the cart.

ΔK=Fd

substitute 28.0N for F and 3.36m for d.

ΔK=28.0×3.36

ΔK=94.08 J

Tension is a force that runs the length of a medium, particularly one that is conveyed by a flexible medium like a rope or cable.

An action-reaction pair of forces acting at either end of the aforementioned elements is what is referred to as tension. Consider a rope; aside from the endpoints, every section of the rope experiences tension force in both directions. The ends feel strained on one side and the force of the attached weight. The tension fluctuates in several places along the string.

Learn more about tension here:

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