P = 1 / n (Celia is first and Felicity is last in line) (n - 1)
P (in the line, Celia and Felicity are next to one another) = 2/n
A class consists of n kids.
These n kids line up for recess.
Out of n kids, there are two kids named Celia and Felicity.
(b) There are n positions and n! ways for n youngsters to stand in a line.
Consequently, n is the entire number of possible situations!
Felicity is standing in the last position while Celia is in the first (fixed position)
The remaining (n - 2) children can stand in the remaining 8 (n - 2) positions! ways
As a result, Celia is first in line and Felicity is last in line for the number of favorable situations, which is (n - 2)!
P (Celia is first in line and Felicity is last in line) = [(n - 2)! / n!]
P = (n - 2)! / [n(n - 1)(n - 2)!]
P = 1 / n(n - 1)
The likelihood that Celia and Felicity are on the same row as one another.
Consider Celia and Felicity as a single student, then multiply by the number of pupils (n - 1)
One can arrange (n - 1) pupils in (n - 1) positions! ways
However, there are two methods to organize Celia and Felicity among themselves.
There are therefore 2 good reasons to put Celia and Felicity adjacent to each other (n - 1)!
P(Celia and Felicity in the line are next to one another) = 2! * (n - 1)! / n!
P = 2 * (n - 1)! / n (n - 1)
P = 2/n
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