Answer:
117.79 m
Step-by-step explanation:
You have an observer 337 m from a skyscraper who measures the angle of elevation from a point 1.75 m above the ground to be 19°. You want to know the height of the skyscraper.
Tangent
The tangent relation tells you ...
Tan = Opposite/Adjacent
Solving for the side opposite the angle, we get ...
Opposite = Adjacent · Tan
Application
In this scenario, the height of the building above the eye height is ...
height above eyes = (337 m)(tan 19°) = 116.038 m
Then the height of the building is ...
skyscraper height = eye height + height above eyes
skyscraper height = 1.75 m + 116.038 m = 117.788 m
The height of the skyscraper is about 117.79 meters.
