JS 19. Evaluate the integral || curlĒ dĞ using Stoke’s Theorem, where F =-yi+xj+ryck and S is the part of the sphere r2 + y2 + 22 = 4 that lies above the cy-planes, oriented upward. A. 27 B. 0 C. 87 D. -87 E. 47

Respuesta :

The integral || curl F || dĞ is equal to -2. The correct answer is therefore option D that is -87.

To evaluate the integral || curl F || dĞ using Stoke's Theorem, we need to find a vector field F and a surface S such that the boundary of S is a closed curve C and the integral is equal to the flux of the curl of F through S. Using the given information, we can find the components of F as:

F = (-y, x, r)

The curl of F is given by:

curl F = (0, 0, 1)

The surface S is the part of the sphere r2 + y2 + z2 = 4 that lies above the cy-planes, oriented upward. This surface can be parameterized by:

x = rcosφcosθ

y = rcosφsinθ

z = rsinφ

where 0 ≤ φ ≤ π and 0 ≤ θ ≤ 2π.

The boundary of S is the curve C, which is the intersection of the sphere and the cy-plane. This curve can be parameterized by:

x = rcosθ

y = rsinθ

z = 0

where 0 ≤ θ ≤ 2π.

Using Stoke's Theorem, the integral || curl F || dĞ is equal to the flux of curl F through S, which is given by:

∫|| curl F || dĞ = ∫curl F · ndC

where n is the unit normal vector to the surface S.

Substituting the expressions for curl F and the parameterizations of S and C, we get:

∫|| curl F || dĞ = ∫(0, 0, 1) · (cosφcosθ, cosφsinθ, sinφ)dC

= ∫(sinφ)dC

= ∫sinθdθ

= [-cosθ]θ=0θ=2π

= -2

Learn more about Stoke's theorem at:

brainly.com/question/13105453

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