20. Let g be a twice-differentiable, increasing function of t. If g(0) 20 and g(10) 220, which of the following must be true on the interval 0 < 10 ? (A) g'(t) 0 for some t in the interval. (B) g) 20 for some t in the interval. (C) g"(t) 0 for some t in the interval. (D) g"(t) > 0 for all t in the interval

Respuesta :

For given function the correct solution is g'(t) = 20 for some t in the interval.

A function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

For a given function, y = F(x), if the value of y is increasing on increasing the value of x, then the function is known as an increasing function and if the value of y is decreasing on increasing the value of x, then the function is known as a decreasing function.

Given that g(10)= 220

g(0)= 20

So putting values in condition of differentiation for increasing function we get:

[tex]\frac{g(10)-g(0)}{10-0}[/tex]

= [tex]\frac{220-20}{10}[/tex]

=20

Hence as we can see that the correct solution for given function is g'(t) = 20 .

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