Respuesta :
The percentage of data that falls between 1.9 inches and 2.3 inches of rainfall is roughly (D) 68% if the distribution is normal.
What is the percentage?
In essence, percentages are fractions with 100 as the denominator.
We place the percent symbol (%) next to the number to indicate that the number is a percentage.
For instance, you would have received a 75% grade if you answered 75 out of 100 questions correctly on a test (75/100).
So, we determine each's z-score:
z-score = (x-mean)/SD
z1 = (1.9-2.1)/0.2 = -1
z2 = (2.3-2.1)/0.2 = 1
Then, the percentage we want to determine is:
P(-1<x<1)
For this, we utilize the normal scoring table:
P(-1<x<1) = P(x<1) -P(x<-1) = 0.68269
= 68%
Therefore, the percentage of data that falls between 1.9 inches and 2.3 inches of rainfall is roughly (D) 68% if the distribution is normal.
Know more about percentages here:
https://brainly.com/question/9553743
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Complete question:
The average daily rainfall for the past week in the town of Hope Cove is normally distributed, with a mean rainfall of 2.1 inches and a standard deviation of 0.2 inches. If the distribution is normal, what percent of data lies between 1.9 inches and 2.3 inches of rainfall? a) 95% b) 99.7% c) 34% d) 68%
