bowl a contains 2 red chips; bowl b contains two white chips and 1 red chip, and bowl c contains 1 red chip and 1 white chip. a bowl is selected at random, and one chip is taken at random from that bowl. if the selected chip is white, what is the probability that the chip belongs to bowl c?

Probabilities can be expressed as proportions with a 0–1 range or as percentages with a 0%–100% range. If an event has a probability of 1, it is very certain to occur; if it has a probability of 0, it has no chance of occurring. There are 45 chances out of 100 that an event will occur when its probability is 0.45 (45%).

Here,

A : 2 Red chips

B : 2 White chips

C: One Red and one White chip

P(selecting any bowl) = 1/3

1) We have to find P(W).

The selected chip can be white if it is either selected from Bowl B or Bowl C.

Symbolically this can be written as

P(W) = P(Bowl B and White chips) + P(Bowl A and White chips)

P(W) = [(1/3) × 1/1)] + [(1/3) × (1/2)]

P(W) = (1/3) + (1/6)

P(W) = 1/2

P(W) = 0.5

2) There is only one bowl with both of white and red chips and that bowl is bowl C. So it is possible the other chips in the bowl to red only if it has been selected from Bowl C.

So ,We need to find P(Bowl C | W).

P(Bowl C | W) = P(Bowl C and W)/P(W)

P(Bowl C | W) = (1/3) × (1/2)/(1/2)

P(Bowl C | W) = 1/3

Hence, the required probability is 1/3.

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