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Three electromagnetic waves travel through a certain point P along an x axis. They are polarized parallel to a y axis, with the following variations in their amplitudes. Find their resultant at P
E1 =(10.0μV/m)sin[(2.0×10^14rad/s)t]
E2 =(5.00μV/m)sin[(2.0×10^14rad/s)t+45.0∘]
E3 =(5.00μV/m)sin[(2.0×10^14rad/s)t−45.0∘]

Respuesta :

Their resultant at point P is 17.07μV/m

The   amplitude of first wave,a1 = 10.0μV/m

The   amplitude of second wave, a2 = 5.00μV/m

The   amplitude of third wave, a3 = 5.00μV/m

Phase angle of first wave, θ1  = 0°

Phase angle of second wave, θ2 = 45°  

Phase angle of third wave , θ3 = -45°

Their resultant at point P is given by ,

R =  a1 Cosθ1 + a2 Cos θ2 + a3 Cosθ3

  = 10 * Cos0 + 5 * Cos(45) + 5 * Cos(-45)

   =17.07μV/m

To learn more about resultant of amplitude of a wave below is the given link:

https://brainly.com/question/1704101

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